T-SQL 解决"易语言难题"

declare @i int
declare @j int
declare @str varchar(20)
set @i = 123
while @i < 999/3
begin
	select @str = convert(varchar,@i)  +' '+ 
		      convert(varchar,@i*2)+' '+
		      convert(varchar,@i*3), 
		      @j = 1, @i = @i + 1
	while @j <= 9	
	begin
		if charindex(convert(varchar,@j),@str) <= 0 break
		set @j = @j + 1
	end
	if @j >= 10 print @str
end